if 1.5 moles of oxygen combine with Al to form Al2O3 , the mass of Al in gram used in this reaction (atomic mass of Al =27)
Answers
Answered by
2
Answer:
4Al + 3O2 ---> 2Al2O3
1mole O2 = 32g * 1.5mole = 48g * 2 = 96g
Al2O3 = 101.96g/mole * 2 = 203.92g
203.92g - 96g O2 = 107.92g.
Therefore,
The weight of Al in the reaction of 1.5moles of O2 is 107.92g
Answered by
10
Answer: 40.5 g of Al
Explanation:
2Al + 3 O2 --->2 Al2O3
1 mole = 27 gm of Al
1.5 mole = x gm of Al
x = 1.5 × 27
= 40.5 gm
Hence mass of Al used is 40.5 g .
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