Question

if 1/5 of a number exceeds 1/7 same number by 36.find the number​

Answer 1

Let the number be "x".

So,

• $\sf{\dfrac{1}{5} \ of \ the \ number = \dfrac{x}{5}}$

• $\sf{\dfrac{1}{7} \ of \ the \ number = \dfrac{x}{7}}$

From the question:

$\sf{\implies \dfrac{x}{5}-\dfrac{x}{7}=36}$

$\sf{\implies \dfrac{7x-5x}{5\times 7}=36}$

$\sf{\implies \dfrac{2x}{35}=36}$

$\sf{\implies 2x=36\times 35}$

$\sf{\implies 2x=1260}$

$\sf{\implies x=\dfrac{1260}{2}}$

$\sf{\implies x=630}$

$\huge{\boxed{\sf{\therefore Number=630}}}$