Question

if 1.5 % of items produced by manufacturing units are known to be defective what is the probability that a sample of 200 items would contain no defective items​

Answer 1

Answer:

please mark it as a brainliest answer

Answer 2

Answer: 0.985

Step-by-step explanation:

As given 1.5% of items produced by manufacturing units are defective

now we take a sample of 200 units

Number of defectives units = $1.5\% \text { of } 200 = \dfrac{1.5}{100} \times 200 = 1.5\times 2 = 3$

Therefore non defective items = 200- 3 = 197

E: non defective items

$Probability = \dfrac{\text {Favourable outcomes} }{\text {Total number of outcomes} }\\\\P(E)= \dfrac{197}{200} = 0.985$

Hence, the probability of non defective item is 0.985