Question

If 1-5y is a factor of the polynomial 5y^3-y^2+4y+a.Find the value of a.

Answer 1

Answer:

a=-4/5

Step-by-step explanation:

Given:- 1-5y is a factor of polynomial 5y^3-y^2+4y+a.

So, 1-5y =0

y =1/5

Substituting value of y in equation.

5*(1/5)^3+(1/5)^2+4*(1/5)+a=0

5*1/125 + 1/25 + 4/5 +a=0

1/25 + 1/25 + 4/5 +a=0.

Taking lcm as 25

1-1+20+25a/25=0

By cross multiplication,

20+25a=0

5(4+5a)=0

4+5a=0

a=-4/5