Question

If, 1 ♦ 6 = 64 , and 7 ♦ 8 = 256, ​ Find the value of 3 ♦ 9.​

Answer 1

Answer:

169

Step-by-step explanation:

In first, {(1+6)+1}² =64

In second, {(7+8)+1}² = 256

In third, {(3+9)+1}² = 169

In all cases first the sum of number, then adding 1 to the result and then square it.

Answer 2

Answer:

Here we should find the logic between every given terms and should apply that same logic into 3 ♦ 9.​ Final Answer: $169$

Step-by-step explanation:

From the given given question,

• Take the first value  1 ♦ 6 = 64. Logic for this value is,

Step 1: Add $1$ and $6$ →  $1+6=7$

Step 2: Add $1$ and step 1 answer $(7)$ → $1+7=8$

Step 3: Square the step 2 answer →  $8^{2}=64$

• Take the second value 7 ♦ 8 = 256. Logic for this value is,

Step 1: Add $7$ and $8$ →  $7+8=15$

Step 2: Add $1$ and step 1 answer $(15)$ → $1+15=16$

Step 3: Square the step 2 answer →  $16^{2}=256$

• Similarly, apply this logic into 3 ♦ 9.

Step 1: Add $3$ and $9$ →  $3+9=12$

Step 2: Add $1$ and step 1 answer $(12)$ → $1+12=13$

Step 3: Square the step 2 answer →  $13^{2}=169$

Final Answer: 3 ♦ 9 $=169$