Question

if 1÷√7-2 = a√7+b find a and b​

Answer 1

Answer:

$\frac{1}{ \sqrt{7 - 2} } = a \sqrt{7 + b}$

a=

$\frac{1}{7 - 2}$

b= -2

$\frac{1}{7 - 2} \times \sqrt{7 + ( - 2)}$

root 7 minus 2 cancels out with 7 - 2 which is the The denominator of 1,gives 1/ root 7 minus 2