Question

If ×=1/7,y=2/3and z= -1/3,verify that,x×(y+z)=(x×y)+(x×z).
Please answer guys fast ​

Answer 1

Given:-

• $x=\dfrac{1}{7}$

• $y=\dfrac{2}{3}$

• $z=\dfrac{-1}{3}$

To Verify:-

• $x(y + z) = (x×y)+(x×z)$

Solution:-

Simply substituting the Values,

$⟹x(y + z) = (x×y)+(x×z)$

$⟹\dfrac{1}{7}(\dfrac{2}{3} + \dfrac{-1}{3}) = \dfrac{1}{7}×\dfrac{2}{3}+\dfrac{1}{7}×\dfrac{-1}{3}$

$⟹\dfrac{1}{7}×\dfrac{1}{3} = \dfrac{2}{21}+\dfrac{-1}{21}$

$⟹\dfrac{1}{21}= \dfrac{1}{21}$

${\boxed{L.H.S = R.H.S}}$

Hence Verified.