If 1.8*10^19 molecules of NO2 are removed from 10mg of NO2, How many moles of NO2 are left?
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no of moles left is equal to 1.95*10^-20 . You can see my attachment for detail... if u satisfied with my answer then mark it as brainlist answer
Attachments:
AkshuSamdani:
where is the attachment
now see
answer is 1.87*10^-4
i think u know the formula
ok let me check my answer
Its 10 mg so in gm it will be 0.01
yaa i got my mistake
wait i am uploading new attachment
When you will upload
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