if 1/8 of a pencil is black,1/2 of the remaining is white and the remaining,3/2cm is blue,find the total lenth of the pencil
Answers
Answered by
103
Let total length of pencil be x cm.
Then, black part = x/8
Remaining part pencil after black part = x - x/8 = 7x/8
then White part = 1/2 (7x/8)
= 7x/16
Now Remaining part of pencil is blue = total length of pencil - (length of black part + length of white part)
length of blue part of pencil = x - (x/8 + 7x/16)
length of blue part of pencil = x - (2x + 7x)/16
length of blue part of pencil = x - 9x/16
length of blue part of pencil = (16 x - 9x)/16
∴ Length of blue part = 7x/16;
According to question
Length of blue part = 31/2
7x/16 = 31/2
⇒ 7x/16 = 7/2
⇒ x/16 = 1/2
⇒ x = 16/2
∴ x = 8 cm
Then, black part = x/8
Remaining part pencil after black part = x - x/8 = 7x/8
then White part = 1/2 (7x/8)
= 7x/16
Now Remaining part of pencil is blue = total length of pencil - (length of black part + length of white part)
length of blue part of pencil = x - (x/8 + 7x/16)
length of blue part of pencil = x - (2x + 7x)/16
length of blue part of pencil = x - 9x/16
length of blue part of pencil = (16 x - 9x)/16
∴ Length of blue part = 7x/16;
According to question
Length of blue part = 31/2
7x/16 = 31/2
⇒ 7x/16 = 7/2
⇒ x/16 = 1/2
⇒ x = 16/2
∴ x = 8 cm
Answered by
49
total X cm
black= x/8
remain= x-x/8=7x/8
white=1/2(7x/8)=7x/16
● 7x/16=7/2
x=8cm
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