Math, asked by gonigintalas23, 10 months ago

If 1 ! 9=20, 9 ! 5 =28, and 5 ! 5 = 20 then find the value of 7!3=?

Answers

Answered by gadakhsanket
5

Hii Dear,

◆ Answer -

7!3 => 20

◆ Explanation -

You'll find a relationship between the numbers if you see observe carefully.

Twice the sum of 1st & 2nd digit gives us the answer.

1!9 => 2(1+9) = 20

9!5 => 2(9+5) = 28

5!5 => 2(5+5) = 20

Using same relationship,

7!3 => 2(7+3) = 20

Best luck buddy...

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