Question

If 1/a+1/b+1/c = 0 and a + b + c = 9, find the value of a-3 + b-3 + c-3 –3abc.?

Answer 1

Step-by-step explanation:

First we find the value of a

2

+b

2

+c

2

a

2

+b

2

+c

2

=(a+b+c)

2

−2(ab+bc+ca)=8

2

−2×19=64−38=26

∴a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ca)=(8)(26−19)=8×7=56

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