if 1/a , 1/b , 1/c are in A.P. prove that bc , ca , ab are in A.P
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Answered by
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Step-by-step explanation:
2/b=1/a+1/c
2/b=(a+c)/ac
2ac=b(a+c)
2ac=bc + ab
It satisfies condition for AP so it is AP
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