if 1/a+1/b+1/c equal 0 then a2+b2+C2 equal to
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Given
1/a+1/b+1/c =0
a+b+c=0
To find
a²+b²+c²
Solution
1/a+1/b+1/c =0
- Taking lcm abc
=0
=0
(a+b+c)² =a²+b²+c²+2ab+2bc+2ac
=>0=a²+b²+c²+2×0
=>a²+b²+c²=0
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