Question

if (1/a) + (1/b) = 1 , then which can be the quadratic equation whose roots are a and b​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

x² - (ab)x + ab = 0

We can start by manipulating the given equation to get a common denominator:

1/a + 1/b = 1

(b + a)/(ab) = 1

b + a = ab

Now we can use this expression to write a quadratic equation whose roots are a and b. Recall that if a and b are the roots of a quadratic equation of the form ax² + bx + c = 0, then we have:

x² - (a + b)x + ab = 0

Substituting a + b = ab from above, we get:

x² - (ab)x + ab = 0

This is the quadratic equation whose roots are a and b.

A quadratic equation is an equation of the form:

ax² + bx + c = 0

where x is an unknown variable, and a, b, and c are coefficients that can be real numbers, complex numbers, or even parameters.

The highest power of x in a quadratic equation is 2, and the equation can have at most two solutions, which are called roots or zeros. The roots can be real or complex numbers, depending on the values of the coefficients.

To solve a quadratic equation, we can use various methods, such as factoring, completing the square, or using the quadratic formula:

x = (-b ± √(b² - 4ac))/(2a)

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