Math, asked by shanmugamlatha747, 2 months ago

If 1-a , 3, 2a-1 are three consecutive terms of an AP what is the value of a​

Answers

Answered by amitnrw
2

Given : 1-a , 3, 2a-1 are three consecutive terms of an AP  

To Find :  the value of a​

Solution:

1-a , 3, 2a-1 are three consecutive terms of an AP  

=> (1 - a) + (2a - 1)  = 2 * 3

=> a  = 6

Value of a is 6

Three terms ate

-5  ,  3  , 11

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Answered by pulakmath007
2

SOLUTION

GIVEN

1 - a , 3, 2a - 1 are three consecutive terms of an AP

TO DETERMINE

The value of a

EVALUATION

Here it is given that 1 - a , 3, 2a - 1 are three consecutive terms of an AP

So common difference is same

Second Term - First term = Third term - Second Term

 \implies \sf{3 - (1 - a) = (2a - 1) - 3}

 \implies \sf{3 - 1  +  a = 2a - 1 - 3}

 \implies \sf{  a  + 2= 2a - 4}

 \implies \sf{  a   = 6}

FINAL ANSWER

Hence the required value of a = 6

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