If 1. a=3, d=-2, n=9 find an
2. f=-2, n=22, an=-39 find a
3. a=13, n=5, an=55 find d
4. a=12, d=4, an=56 find n
Answers
Answer:
1. The nᵗʰ term of the AP is - 13.
2. The first term of AP i. e. a is 3.
3. The common difference ( d ) of the AP is 10.5.
4. The value of n of the AP is 12.
Step-by-step-explanation:
1.
We have given that,
- a = 3
- d = - 2
- n = 9
We have to find aₙ.
We know that,
aₙ = a + ( n - 1 ) × d - - [ Formula ]
→ a₉ = 3 + ( 9 - 1 ) × ( - 2 )
→ a₉ = 3 + 8 × ( - 2 )
→ a₉ = 3 - 16
→ a₉ = - 13
∴ The nᵗʰ term of the AP is - 13.
─────────────────────
2.
We have given that,
- d = - 2
- n = 22
- aₙ = - 39
We have to find the first term of AP i. e. a.
By using the formula, aₙ = a + ( n - 1 ) × d, we get,
→ - 39 = a + ( 22 - 1 ) × ( - 2 )
→ - 39 = a + 21 × ( - 2 )
→ - 39 = a - 42
→ a = - 39 + 42
→ a = 3
∴ The first term of AP i. e. a is 3.
─────────────────────
3.
We have given that,
- a = 13
- n = 5
- aₙ = 55
We have to find the common difference i. e. d.
By using the formula, aₙ = a + ( n - 1 ) × d, we get,
→ 55 = 13 + ( 5 - 1 ) × d
→ 55 = 13 + 4d
→ 55 - 13 = 4d
→ 4d = 42
→ d = 42 / 4
→ d = 10.5
∴ The common difference ( d ) of the AP is 10.5.
─────────────────────
4.
We have given that,
- a = 12
- d = 4
- aₙ = 56
By using the formula, aₙ = a + ( n - 1 ) × d, we get,
→ 56 = 12 + ( n - 1 ) × 4
→ 56 - 12 = ( n - 1 ) × 4
→ 44 = ( n - 1 ) × 4
→ ( n - 1 ) = 44 ÷ 4
→ n - 1 = 11
→ n = 11 + 1
→ n = 12
∴ The value of n of the AP is 12.