Question

☆ If 1, a, b, c,16 are in G.P.(a, b, c are positive), then value of a+b+c is : 

(a) 16

(b) 14

(c) 12

(d) 8

​

Answer 1

Answer:

Given a,b,c are in GP.

b/a = c/b

b2 = ac

Given equation (log a)x2-(2log b)x + log c = 0

(log a)x2-(log b2)x + log c = 0

(log a)x2-(log ac)x + log c = 0 (since b2 = ac)

x log a(x-1) – log c(x-1) = 0

(x log a – log c)(x-1) = 0

(x log a – log c) = 0 or x-1 = 0

x = (log c/log a) or x = 1

Answer 2

Answer:

Happy Independence Day to all....