If 1 a zero of polynomials p(x) = a - 3(a-1) x-1,then find a
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P(x)=ax²-3(a-1)x-1
we know P(1)=0
a (1)²-3(a-1)·1-1=0
a-3(a-1)-1=0
a-3a+3-1=0
-2a+2=0
-2a=-2
a=1
we know P(1)=0
a (1)²-3(a-1)·1-1=0
a-3(a-1)-1=0
a-3a+3-1=0
-2a+2=0
-2a=-2
a=1
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