Question

If 1&2 are the zeros of the quadratic polynomial, then find the quadratic polynomial.​

Answer 1

Step-by-step explanation:

To find: Quadratic Polynomial.

where , ( α + β ) is sum of zeroes and αβ is product of zeroes.

Here, α = - 4 and β = 2. ⇒ α + β = -4 + 2 = -2.

αβ = -4 × 2 = -8. ⇒ Quadratic Polynomial = k ( x² - ( -2 ) x + ( -8 ) ) = k ( x² + 2x - 8 ) Therefore, Quadratic Polynomial is k ( x² + 2x - 8 )

Answer 2

Answer:

if 1 and 2 are zeroes of polynomial so sum of zeroes = 3 and product of zeroes = 2

Step-by-step explanation:

so quadratic polynomial =

$p{x} = {x -}^{2} - \alpha \: x - \: \beta x + \alpha \times \beta$

${x }^{2} - 3x + 2$

is the right answer

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