If 1 and -1 are zeroes of polynomial.
P(x) = ax^3 + x^2- 2x+b .find a and b.
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Here is your answer
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realpokemonfan:
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let x=1
p(x) = a(1) ^3+1^2-2(1) +b
p(x) = a+1-2+b
p(x) =a-1+b..... (1)
let x=-1
p(x) =a(-1) ^3+(-1) ^2-2(-1) +b
p(x) = -a+1+2+b
p(x) =-a+3+b.... (2)
by add (1) and (2).
a-1+b
-a+3+b
=4+2b
=2b=-4
=b=-2
put above values in (1) equation
p(x) =a-1+(-2)
p(x) =a-1-2
p(x) = a-3
p(x) = a=3
so values of a=3
b=-2
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