if 1 and -1 are zeroes of the polynomial Lx4+Mx3+Nx2+Rx+P, show that L+N+P=M+R=0
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1 is zero of polynomial.
substitute 1 in place of x and equate to zero
L(1)^4+M(1)^3+N(1)^2+R(1)+P=0
L+M+N+R+P=0----------(1)
-1 Is zero of polynomial
sub -1 in place of x
L-M+N-R+P=0
L+N+P=M+R----(2)
From 1&2 we get L+N+P=M+R=0
substitute 1 in place of x and equate to zero
L(1)^4+M(1)^3+N(1)^2+R(1)+P=0
L+M+N+R+P=0----------(1)
-1 Is zero of polynomial
sub -1 in place of x
L-M+N-R+P=0
L+N+P=M+R----(2)
From 1&2 we get L+N+P=M+R=0
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... hope it helps ..
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