if 1 and -1 has zeros of polynomial px = ax^3+x^2-x+b find the value of a and b
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Shivmastaer:
Why u reporting again and again.... Can u justify the mistake
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Answer: a=1 and b= - 1
Step-by-step explanation:
P(x) = ax³+ x² - x + b
Zeroes= 1 and - 1
THEREFORE BY FACTOR THEOREM
P(1)=0 and p(-) =0
P(1) = a(1)³+(1)²-1 + b = 0
a+1-1+b=0
a+b=0
a = -b
p(-1)= a(-1)³+(-1)²-(-1)+b=0
-a+1+1+b=0
-a+b+2=0
-a+b= - 2
AS a = -b
-(-b) + b = - 2
b + b= - 2
2b=-2
(b = -1)
AS a=-b
a=-(-1)
(a = 1)
HOPE IT HELPS......
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Saiman pls reply before reporting and pls tell the mistake
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for the answer
Why are u reporting bro
Again nd again
If really answer helped you... You can tap on thanks.... But pls don't report
firstly I don't think that your answer is right but I am now realised that your answer is right thanks a lot
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