Question

If 1 and -2 are the zeroes of polynomial x^3-4x^2-7x+10, then find the 3rd zero

Answer 1

Answer:

5

Step-by-step explanation:

$x^{3}-4x^{2}-7x+10$ = 0

a = 1, b = -4, c = -7, d = 10

Given 1 and -2 are the two roots of the polynomial

Let the other root be $\alpha$

We know that

Sum of roots = -b/a

⇒ 1+ (-2) +$\alpha$ = -(-4)/1

⇒$\alpha$ - 1 = 4

∴ $\alpha$ = 5

The third root is 5

Answer 2

Step-by-step explanation:

hope it's helpful dear friend

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