If 1 and -2 are the zeros of the polynomial (x^3-4x^2-7x+10) find its third zero
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Answer:
5
Step-by-step explanation:
Given,
p(x) = x³ - 4x² - 7x + 10
Zeroes = 1 and (-2)
Sum of the zeroes = -(-4)/1 = 4
which is -coefficient of x²/coefficient of x³
Third zero = 4 - 1 - (-2)
= 3 + 2
= 5
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