if 1 and 2 are two zeroes of the polynomial x^3-6x^2 +ax+b then find the valve of a and b
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Given :-
- 1 and 2 are two zeroes of polynomial x³-6x²+ax+b.
To find :-
- Value of a and b.
Solution :-
Since , 1 and 2 are zeroes of the polynomial,
p(1) and p(2) will be 0.
▬▬▬▬▬▬▬▬▬▬▬▬
➾ For p(1) = 0,
➾For p(2) = 0
♣ Substracting equation 1 by equation 2 we get,
➥2a+b-(a+b) = 16-5
➥2a+b-a-b = 11
➥a = 11
➣Putting a = 11 in equation 1 we get,
➥a+b = 5
➥11+b = 5
➥b = -6
∴Value of a is 11 and b is -6.
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