If 1 and -2 are two zeros of the polynomial x3-4x2-7x+10,find its third zero
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Answer:
Step-by-step explanation:
If options are given you can substitute
(Or)
First do long division for that cubic equation by any one zero you will get one quadratic equation now solve that you will two zeros in that any one zero will be your answer..
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Answered by
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Answer:
Let p(x)=x³-4x²-7x+10
Let alpha, beta, gama are zeroes of p(x)
alpha+beta+gama= -b/a
1+(-2)+gama= -(-4)
-1+gama=4
gama= 3
the third zero of the polynomial is 3
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