If λ1 and λ2 denotes the de Broglie wavelength of two particles with same masses but charges in the ratio
of 1:2 after they are accelerated from rest through the same potential difference, then
(A) λ1 > λ2
(B) λ1 = λ2
(C) λ1 < λ2
(D) None
Answers
Answered by
2
Answer:
option 1 is correct
lemda =h/√2mqV here h is plank constant , m is mass , q is charge and V is potential ,,, mass ratio is m1/m2=1/2 so using the formula lemda 1/lemda2=√m2/√m1 [m1/m2=1/2] then lemda 1/lemda2=√2/√1 so lemda 1>lemda2
Answered by
2
Answer:
Option (A) is the right answer!
Explanation:
refer attachment for explanation!!!
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