Question

if 1 and _3 are the zeros of x^3_ax^2_13x+b find the value of a and b​

Answer 1

Answer:

P(1)=0

1^3-a(1)^2-13(1)+b=0

3-a-13+b=0

b=a+10----------(1)

P(-3)=0

(-3)^3-a(-3)^2-13(-3)+b=0

(-27)-9a+39+b=0

12-9a+a+10=0. (using 1)

22-8a=0

8a=22

a=22/8=11/4

b=11/4+10=51/4.