if 1 and -5 are two of the zeroes of polynomial p ( x ) = x cube + 11 x square +23 x -35 find all the zeroes of p( x) .
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Given two zero of equation 1 are 1 , & -5 if α,β,γ are zero of equation 1. the
now α,β,γ=−11,
α=−11−(β+γ)=−11−(1−5)
α=−11+4
[α=−7]
Hence its third zero is -7.
Answered by
0
Answer:
Given two zero of equation 1 are 1 , & -5 if α,β,γ are zero of equation 1.
now,
α,β,γ=−11,
α=−11−(β+γ)=−11−(1−5)
α=−11+4
[α=−7]
Hence its third zero is -7.
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