Math, asked by aayush7696, 10 months ago

if -1 and three are the roots of x square + px + Q is equal to zero find the values of P and Q​

Answers

Answered by gouravmahor
0

Answer:

p=2,Q=-3

Step-by-step explanation:

given that{दिया है}: 1 and 3 are the roots of x²+px+Q {1तथा 3 समीकरण x^2 +px+Q के मूल या शुन्यक है}

we know that ,[हम जानते हैं]

multiple of roots (a×b) = constant/

multiple of x²

मूलो का गुणनफल (a×b) = अचर /x^2 का गुणांक

-1×3= Q/1

Q=-3

sum of roots (a+b) = -multiple of x/

multiple of x²

मूलो का योगफल (a+b) = x का गुणांक/x^2का गुणांक

-1+3 = p/1

p = 2..

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Answered by chandana1932007
0

Answer:

p=-2 q=-3

Step-by-step explanation:

given

x = -1 or 3

when x = -1

x^2px+q=0

(-1)^2+p(-1)+q=0

1-p+q=0

-p+q=-1

p-q=1------------------equation 1

when x = 3

x^2px+q=0

(3)^2+p(3)+q=0

9+3p+q=0

3p+q=-9-------------------------equation 2

by simultaneous linear equation

p   - q = 1-------*3

3p + q =-9-------*1

so,

3p-3q= 3

3p+q  =-9

(-)   (-)     (+)

0-4q=12

-q=12/4

-q=3

q = -3

substituting value of q in equation 1

p - q = 1

p - (-3) = 1

p+3=1

p = 1 - 3

p = -2

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