if -1 and three are the roots of x square + px + Q is equal to zero find the values of P and Q
Answers
Answer:
p=2,Q=-3
Step-by-step explanation:
given that{दिया है}: 1 and 3 are the roots of x²+px+Q {1तथा 3 समीकरण x^2 +px+Q के मूल या शुन्यक है}
we know that ,[हम जानते हैं]
multiple of roots (a×b) = constant/
multiple of x²
मूलो का गुणनफल (a×b) = अचर /x^2 का गुणांक
-1×3= Q/1
Q=-3
sum of roots (a+b) = -multiple of x/
multiple of x²
मूलो का योगफल (a+b) = x का गुणांक/x^2का गुणांक
-1+3 = p/1
p = 2..
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Answer:
p=-2 q=-3
Step-by-step explanation:
given
x = -1 or 3
when x = -1
x^2px+q=0
(-1)^2+p(-1)+q=0
1-p+q=0
-p+q=-1
p-q=1------------------equation 1
when x = 3
x^2px+q=0
(3)^2+p(3)+q=0
9+3p+q=0
3p+q=-9-------------------------equation 2
by simultaneous linear equation
p - q = 1-------*3
3p + q =-9-------*1
so,
3p-3q= 3
3p+q =-9
(-) (-) (+)
0-4q=12
-q=12/4
-q=3
q = -3
substituting value of q in equation 1
p - q = 1
p - (-3) = 1
p+3=1
p = 1 - 3
p = -2
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