Question

if 1/b+c 1/c+a 1/a+b are in ap then prove that a2, b2,c2 is above ap? ​

Answer 1

Answer:

If a^2 , b^2 and c^2. are in A.P. , then prove that 1/(b+c),1/(c+a),1/(a+b) are in A.P.?

a^2. , b^2. , c^2. are in A.P.

by adding a.b+b.c+c.a. in. each. term.

a^2+a.b+b.c+c.a. , b^2+a.b+b.c+c.a. , c^2+a.b+b.c+c.a are in A.P.

(a+b)(c+a). , (a+b) (b+c). , (b+c)(c+a). are in A.P.

On dividing by (a+b).(b+c).(c+a) in each term

or. 1/(b+c). , 1/(c+a). , 1/(a+b). are in A.P. , proved

Answer 2

Step-by-step explanation:

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