Question

if (1-b) is a root of a quadratic equation x2 + bx + 1 - b =0 then its roots are​

Answer 1

Answer:

hope this answer helps you......

Answer 2

Answer:

Step-by-step explanation:

Let f(x)=x²+bx+1-b=0

If 1-b is a root of f(x) , then,

b-1=0

⇒b=1

So,

Putting the value of b=1 in f(x),

f(x)=x²+(1)x+1-1=0

   ⇒x² + x =0

   ⇒x(x+1)=0

   Either

x=0

   Or,

x=-1  

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