Question

if (1-b) is a root of x^2+bx+(1-b)=0 then find the other root​

Answer 1

Answer:

1

Step-by-step explanation:

Here (1-b) is a root.

as product of roots =

$\alpha \beta = \frac{c}{a}$

so..

$(1 - b) \times \beta = \frac{1 - b}{1}$

then.

$\beta = 1$

hope it helps

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