if 1 by b + c, 1 by C + A, 1 by a + b are in AP then
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Step-by-step explanation:
यदि a , b और c A.P. में हो तो
2b = a + c
अतः 2(1/c+a) = (1/b+c) + (1/a+b)
2/c+a = (a + 2b + c)/(a+b)(b+c)
2(a+b)(b+c) = (a+2b+c)(a+c)
2(ab+ac+b²+bc)=a²+2ab+ac+ac+2bc+c²
2ab+2ac+2b²+2bc=a²+2ab+2ac+2bc+c²
2b² = a² + c²
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