if 1+cos^2A=3cosAsinA,find the value of cotA
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1 + cos^2A= 3cosA sinA
1 +( 1 - sin^2A )=3cosA sinA
2 - sin^2A = 3 (cosA sinA )
( 2 - sin^2 A ) / cosA sinA = 3
( 2 /cosAsinA - sin^2A/ cosA sinA = 3
2secA cosecA - tanA = 3
2secA cosecA - 3 = tanA
tanA = 2secA cosecA - 3
now as we know that
cot A = 1 / tanA
cot A = 1 / ( 2secA cosecA - 3 )
1 + cos^2A= 3cosA sinA
1 +( 1 - sin^2A )=3cosA sinA
2 - sin^2A = 3 (cosA sinA )
( 2 - sin^2 A ) / cosA sinA = 3
( 2 /cosAsinA - sin^2A/ cosA sinA = 3
2secA cosecA - tanA = 3
2secA cosecA - 3 = tanA
tanA = 2secA cosecA - 3
now as we know that
cot A = 1 / tanA
cot A = 1 / ( 2secA cosecA - 3 )
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