If(1+cosA)(1-cosA)=3/4, find secA
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(a+b)(a-b) = a²-b²
(1+cosA)(1-cosA) = 3/4
1-cos²A = 3/4
sin²A = (3/4)
sinA = √3/2
therefore, opposite side=√3; hypotenuse=2
so, adjacent side=1
secA = hypotenuse/adjacent
secA = 2/1 = 2
(1+cosA)(1-cosA) = 3/4
1-cos²A = 3/4
sin²A = (3/4)
sinA = √3/2
therefore, opposite side=√3; hypotenuse=2
so, adjacent side=1
secA = hypotenuse/adjacent
secA = 2/1 = 2
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