Question

if 1–cosa/sina=√2–1 then find the 1+cosa/sina=then

Answer 1

Answer:

$\frac{1-cosA}{sinA} =\sqrt{2} -1\\\frac{sinA}{1-cosA} =\frac{1}{\sqrt{2}-1 } \\\frac{sinA}{1-cosA}* \frac{1+cosA}{1+cosA}= \frac{1}{\sqrt{2}-1 } *\frac{\sqrt{2}+1 }{\sqrt{2}+1 } \\\frac{sinA(1+cosA)}{1-cos^{2}A } =\frac{\sqrt{2}+1 }{2-1}\\\frac{sinA(1+cosA)}{sin^2A} =\sqrt{2}+1 \\\frac{1+cosA}{sinA} = \sqrt{2}+1$