Question

If (1/cosecθ – 1) + (1/cosecθ + 1) = 2secθ, 0°<θ<90°, then the value of (cotθ + Cosθ) is

Answer 1

Answer:

Kal tera bhi boards hai kya? Same here

Step-by-step explanation:lol

Answer 2

Answer:

(2+√2)/2

Step-by-step explanation:

1/(1/sinθ-1)+1/(1/sinθ+1)=2secθ

sinθ/(1-sinθ)+sinθ/(1+sinθ)=2secθ

(sinθ(1+sinθ)+sinθ(1-sinθ))/((1-sinθ)(1+sinθ))=2secθ

(sinθ+〖sin〗^2 θ+sinθ-〖sin〗^2 θ)/((1-〖sin〗^2 θ))=2secθ

2sinθ/(〖cos〗^2 θ)=2secθ

2tanθsecθ=2secθ

tanθ=1

∴θ=〖45〗^°

cotθ+cosθ=cot45+cos45

=1+1/√2

=(√2+1)/√2

=(2+√2)/2