If 1+costhetha/1-costheta=16/9 then 1+ tantheta/1-tantheta =
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Answered by
3
Answer:
1+cosθ=2cos
2
(
2
θ
)
1−cosθ=2sin
2
(
2
θ
)
Hence substituting in the above equation, we get
cot
2
2
θ
=
9
16
cot(
2
θ
)=
3
4
tan(
2
θ
)=
4
3
Now
tan(θ)=
1−tan
2
2
θ
2tan
2
θ
=
1−
16
9
2
3
=
7
24
Therefore
1−cotθ
1+cotθ
=
24−7
24+7
=
17
31
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0
Answer:
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