. If 1 g of HCl and 1 g of MnO2 heated together the maximum weight of Cl2 gas evolved will be :[MnO2 + 4HCl ⊗ MnCl2 + Cl2 + 2H2O] :
Answers
Explanation:
MnO2+4HCl→Cl2+MnCl2+2H2O
MnO2+4HCl→Cl2+MnCl2+2H2OAs HCl is present in limited amount, it will be limiting reagent and the amount of chlorine gas produced will be calculated according to the amount of HCl present.
MnO2+4HCl→Cl2+MnCl2+2H2OAs HCl is present in limited amount, it will be limiting reagent and the amount of chlorine gas produced will be calculated according to the amount of HCl present.Moles of HCl=36.51
MnO2+4HCl→Cl2+MnCl2+2H2OAs HCl is present in limited amount, it will be limiting reagent and the amount of chlorine gas produced will be calculated according to the amount of HCl present.Moles of HCl=36.51Moles of Cl2=41×36.51
MnO2+4HCl→Cl2+MnCl2+2H2OAs HCl is present in limited amount, it will be limiting reagent and the amount of chlorine gas produced will be calculated according to the amount of HCl present.Moles of HCl=36.51Moles of Cl2=41×36.51Weight of Cl2 gas=41×36.51×71=0.486 gm