Question

If 1 g of sulphur dioxide contains x molecules, what will be the
number of molecules in 1g of methane?​

Answer 1

Answer:

The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :

(i) The molecular formula of sulphur dioxide is SO2.

So, 1 mole of SO2=Mass of S+Mass of 2 'O'

=32+2×16

=64 grams

Now, 64g of sulphur dioxide =1 mole

So, 1g of sulphur dioxide =164 mole

Thus, we have 164 mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, 164 mole of methane will also contain x molecules of methane.

(ii) Molecular formula of methan is CH4

So, 1 mole of CH4 = Mass of C + Mass of 4 H

=12+4×12

Now, 16g of methane = 1 mole

So, 1 g of mathane = 116 mole

We know that :

164 mole of methane contains = x molecules

So, 116 mole of contains will contain =x×6416 molecules

=4x molecules

Explanation:

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Answer 2

Answer:

answer is 4x molecule

Explanation:

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