Question

If 1 g of sulphur dioxide contains x molecules, what will be the
number of molecules in 1g of methane?​

Answer 1

Explanation:

The molecular formula of sulphur dioxide is SO2. Thus, we have 164 mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, 164 mole of methane will also contain x molecules of methane.

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Answer 2

Answer:

o, 1 mole of SO2 = Mass of S + Mass of 2 'O'

                          = 323 + 2 x 16

                           = 64 grams

Now, 64 g of sulphur dioxide = 1 mole

begin mathsize 14px style space space So comma space 1 space straight g space of space Sulphur space dioxide space equals space fraction numerator 1 over denominator 64 space end fraction space mole end style

Thus, we have 1/64 mole of sulphur dioxide and it contains 'X' molecules in it. Now, since equal moles of all the substances contain equal number of molecules, therefore. 1/64 mole of methane will also contain 'X' molecules of methane.

Molecular formula of methane is CH4.

So, 1 mole of CH4 = Mass of C + Mass of 4 H

                          = 12 + 4  1

                          = 16 grams

Now, 16 g of methane = 1 mole

so, 1 g of methane = 1/64 mole

We know that,

1/64 mole of methane contains = 'X' molecules

begin mathsize 14px style space space So comma space 1 divided by 16 space mole space of space methane space will space contain space equals space fraction numerator straight X space cross times space 64 over denominator 16 end fraction space molecules end style

                                                      = 4X molecules

Thus, if 1 g of

Explanation: