Question

If 1 gm of gold 10 carats fine, 1 gm of gold 11 carats fine, 2 gm of gold 12 carats fine, and 5 gm of gold 13 carats fine be mixed together, then the fineness of the resulting compound is​

Answer 1

Answer:

Ix10/24 +1x11/24+2x12/24+5x13/24

(10+11+24 +65), /24=110/24=

= 4.58g of fine gold

Answer 2

Answer:

  12.23gm(approximately)                                                                                                                                                                                                                                                                                                                                                                                                                                        

Step-by-step explanation:

In this question,

We have been given that

1gm of gold 10 carats fine;

1gm of gold 11 carats fine;

2gm of gold 12 carats fine;

5gm of gold 13 carats fine;

These all are mixed together,We have to find the Fineness of the resulting compund.

Total grams of gold = 1+1+2+5=9gms

Fineness=10×$\frac{1}{9}$+11×$\frac{1}{9}$+12×$\frac{2}{9}$+13×$\frac{5}{9}$

Fineness=$\frac{10}{9}+\frac{11}{9}+\frac{24}{9}+\frac{65}{9}$

Fineness=$\frac{110}{9}$

Fineness=12.23grams

Hence,Fineness of thr gold is 12.23grams