Question

If 1 gram of substance of relative density 2 and 4 gram of the another substance of relative density 3 are mixed together then the relative density of mixture is

Answer 1

let substance 1 be A

& substance 2 be B

rel den of A = 2

given mass = 1g

rel density of B = 3

given mass = 4g

= 2/1+3/4

→LCM = 4

= 4×2 + 3÷4

= 11÷4

= 2.7

Hope it helps

Answer 2

Answer:

Relative density of the mixture = density of the mixture/density of water 2.72.

Explanation:

Step 1: Relative density is the ratio of density of a substance to the density of water.

So, Density of the substance =Relative density x density of water

Hence for the substance m=1g, relative density= 2

Step 2: Density = 2 x 1= 2g/cc [density of water is 1g/cc]

Density = Mass/Volume

2g/cc = 1g/v

v = 1/2cc

for the substance m=4g, relative density = 3

density = Relative density x density of water = 3 x 1 = 3g/cc

density = mass/v1

3 = 4/v1

v1 = 4/3cc

Step 3: When they are mixed together total mass = 1+4 = 5g, and total volume = 1/2 + 4/3 = 11/6cc

density = m/v = 5/(11/6) = 30/11 = 2.72g/cc

Hence Relative density of the mixture = density of the mixture/density of water = 2.72/1 = 2.72.

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