if 1 gram of sulphur contains X atoms, calculate the number of atoms in 1 gram of oxygen element
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Answered by
56
1g of S = X atoms
we know that 32g of S = 6.022*10^23 atoms
= 1g of S = {6.022*10^23} /32 =X atoms
= 1g of S = {6.022*10^23} = 32X atoms
Now, 16g of O = 6.022*10^23 atoms
since, 6.022*10^23 atoms = 32X atoms
therefore, 16g of O = 32X atoms
Hence, 1g of O = 2X atoms
we know that 32g of S = 6.022*10^23 atoms
= 1g of S = {6.022*10^23} /32 =X atoms
= 1g of S = {6.022*10^23} = 32X atoms
Now, 16g of O = 6.022*10^23 atoms
since, 6.022*10^23 atoms = 32X atoms
therefore, 16g of O = 32X atoms
Hence, 1g of O = 2X atoms
Answered by
12
Answer:
36 g of Sulphur = 6.023*10^23 atoms
1 g of Sulphur = 6.023*10^23/32 = x atoms
16 g of Oxygen = 6.023*10^23 atoms
1 g of Oxygen = 6.023*10^23/16 atoms = 2*x atoms
Therefore, No. of atoms in 1 g of Oxygen = 2x atoms.
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