if (1+i/1-i )^x= 1 find x
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Answer:
(1+i/1-i)^2 =(1+i^2 +2i)/1+i^2 - 2i
=(1-1+2i)/1-1-2i=-1
(1+i/1-i)^2 =-1
(1+i/1-i)^4 =(-1)2=1
Therefore x =4
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