Question

if (1+i/1-i )^x= 1 find x​

Answer 1

Answer:

(1+i/1-i)^2 =(1+i^2 +2i)/1+i^2 - 2i

=(1-1+2i)/1-1-2i=-1

(1+i/1-i)^2 =-1

(1+i/1-i)^4 =(-1)2=1

Therefore x =4