if (1+i/1-i )^x= 1 find x
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Answer:
(1+i×1+i÷1-i×1-i)^x=1
Step-by-step explanation:
(1+i^2+2i÷1^2-i^2)^x=1 (2i÷2)^x=1. i^x=1. X=4
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