if (1+i/1-i)^x =1 then value of x is
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Answer:
[(1 + i)/(1 - i)]x = 1
[(1 + i)(1 + i)/(1 - i)(1 + i)]x = 1
[(1 + i2 + 2i)/(1 - i2)]x = 1
i2 = -1
(2i/2)x = 1
ix = 1
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Step-by-step explanation:
i^2 = -1 & i^4 = 1
use this concept
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