Math, asked by rs3315877, 7 months ago

if (1+i/1-i)^x =1 then value of x is​

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Answered by harjap73
0

Answer:

[(1 + i)/(1 - i)]x = 1

[(1 + i)(1 + i)/(1 - i)(1 + i)]x = 1

[(1 + i2 + 2i)/(1 - i2)]x = 1

i2 = -1

(2i/2)x = 1

ix = 1

Answered by kalashyam
0

Step-by-step explanation:

i^2 = -1 & i^4 = 1

use this concept

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