If ω ( ≠ 1 ) is a cube root of unity an ( 1 + ω )^7 = A + Bω, then A and B are respectively the numbers
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for cube root of unity
1+ω=-ω²
therefore
(1+ω)^7=(-ω²)^7=-ω^14
as ω³=1
-ω^12(ω²)=-ω²=-(1+ω)=-ω-1
therefore A=-1,B=-1
1+ω=-ω²
therefore
(1+ω)^7=(-ω²)^7=-ω^14
as ω³=1
-ω^12(ω²)=-ω²=-(1+ω)=-ω-1
therefore A=-1,B=-1
Anonymous:
u are regular answerer
Answered by
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the answerr is a= 1 and b = -1.
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