Question

if 1 is a root of quadratic equation ax^2-5 (a-1) x-1=0​

Answer 1

Answer:

3x  

2

+ax−2=0

Since, one root is 1, then x=1

⇒  3(1)  

2

+a(1)−2=0

⇒  3+a−2=0

⇒  a+1=0

⇒  a=−1

⇒  Now, it is given that ax  

2

+6ax−b=0 has equal roots.

∴  b  

2

−4ac=0

⇒  (6a)  

2

−4(a)(−b)=0

⇒  36a  

2

+4ab=0

⇒  36(−1)  

2

+4(−1)b=0                 [ Substituting a=−1 ]

⇒  36−4b=0

⇒  4b=36

∴  b=9

Step-by-step explanation:

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